Solve -10-3x/2<x

$$\frac{ -10-3x }{ 2 } < x$$

Solve for x

$$x>-2$$

Solution Steps

Divide each term of -10-3x by 2 to get -5-\frac{3}{2}x.

$$-5-\frac{3}{2}x<x$$

Subtract x from both sides.

$$-5-\frac{3}{2}x-x<0$$

Combine -\frac{3}{2}x and -x to get -\frac{5}{2}x.

$$-5-\frac{5}{2}x<0$$

Add 5 to both sides. Anything plus zero gives itself.

$$-\frac{5}{2}x<5$$

Multiply both sides by -\frac{2}{5}, the reciprocal of -\frac{5}{2}. Since -\frac{5}{2} is negative, the inequality direction is changed.

$$x>5\left(-\frac{2}{5}\right)$$

Cancel out 5 and 5.

$$x>-2$$