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\frac{5\times \left(-5i\right)+5\left(-5\right)i^{2}}{5}
Multiply 5+5i times -5i.
\frac{5\times \left(-5i\right)+5\left(-5\right)\left(-1\right)}{5}
By definition, i^{2} is -1.
\frac{25-25i}{5}
Do the multiplications in 5\times \left(-5i\right)+5\left(-5\right)\left(-1\right). Reorder the terms.
5-5i
Divide 25-25i by 5 to get 5-5i.
Re(\frac{5\times \left(-5i\right)+5\left(-5\right)i^{2}}{5})
Multiply 5+5i times -5i.
Re(\frac{5\times \left(-5i\right)+5\left(-5\right)\left(-1\right)}{5})
By definition, i^{2} is -1.
Re(\frac{25-25i}{5})
Do the multiplications in 5\times \left(-5i\right)+5\left(-5\right)\left(-1\right). Reorder the terms.
Re(5-5i)
Divide 25-25i by 5 to get 5-5i.
5
The real part of 5-5i is 5.