Solve (3.248*1000)*(5.55*1000)/(3.248*1000)+(5.55*1000)

$$\frac{ (3.248 \times 1000) \times (5.55 \times 1000) }{ (3.248 \times 1000)+(5.55 \times 1000) }$$

Evaluate

$$\frac{9013200}{4399}\approx 2048.920209138$$

Solution Steps

Multiply 3.248 and 1000 to get 3248.

$$\frac{3248\times 5.55\times 1000}{3.248\times 1000+5.55\times 1000}$$

Multiply 3248 and 5.55 to get 18026.4.

$$\frac{18026.4\times 1000}{3.248\times 1000+5.55\times 1000}$$

Multiply 18026.4 and 1000 to get 18026400.

$$\frac{18026400}{3.248\times 1000+5.55\times 1000}$$

Multiply 3.248 and 1000 to get 3248.

$$\frac{18026400}{3248+5.55\times 1000}$$

Multiply 5.55 and 1000 to get 5550.

$$\frac{18026400}{3248+5550}$$

Add 3248 and 5550 to get 8798.

$$\frac{18026400}{8798}$$

Reduce the fraction \frac{18026400}{8798} to lowest terms by extracting and canceling out 2.

$$\frac{9013200}{4399}$$

Factor

$$\frac{3 \cdot 7 \cdot 29 \cdot 37 \cdot 2 ^ {4} \cdot 5 ^ {2}}{53 \cdot 83} = 2048\frac{4048}{4399} = 2048.9202091384404$$