Solve (2x+x)/2*x=48

$$\frac{ (2x+x) }{ 2 } \times x=48$$

Solve for x

$$x=4\sqrt{2}\approx 5.656854249$$

$$x=-4\sqrt{2}\approx -5.656854249$$

Steps by Finding Square Root

Multiply both sides of the equation by 2.

$$\left(2x+x\right)x=96$$

Combine 2x and x to get 3x.

$$3xx=96$$

Multiply x and x to get x^{2}.

$$3x^{2}=96$$

Divide both sides by 3.

$$x^{2}=\frac{96}{3}$$

Divide 96 by 3 to get 32.

$$x^{2}=32$$

Take the square root of both sides of the equation.

$$x=4\sqrt{2} x=-4\sqrt{2}$$

Steps Using the Quadratic Formula

Multiply both sides of the equation by 2.

$$\left(2x+x\right)x=96$$

Combine 2x and x to get 3x.

$$3xx=96$$

Multiply x and x to get x^{2}.

$$3x^{2}=96$$

Subtract 96 from both sides.

$$3x^{2}-96=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 0 for b, and -96 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-96\right)}}{2\times 3}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-96\right)}}{2\times 3}$$

Multiply -4 times 3.

$$x=\frac{0±\sqrt{-12\left(-96\right)}}{2\times 3}$$

Multiply -12 times -96.

$$x=\frac{0±\sqrt{1152}}{2\times 3}$$

Take the square root of 1152.

$$x=\frac{0±24\sqrt{2}}{2\times 3}$$

Multiply 2 times 3.

$$x=\frac{0±24\sqrt{2}}{6}$$

Now solve the equation x=\frac{0±24\sqrt{2}}{6} when ± is plus.

$$x=4\sqrt{2}$$

Now solve the equation x=\frac{0±24\sqrt{2}}{6} when ± is minus.

$$x=-4\sqrt{2}$$

The equation is now solved.

$$x=4\sqrt{2} x=-4\sqrt{2}$$