Solve (2x*(3^2x)/6x

$$\frac{ (2x \times ( { 3 }^{ 2 } x) }{ 6x }$$

Evaluate

$$3x$$

Solution Steps

Multiply x and x to get x^{2}.

$$\frac{2x^{2}\times 3^{2}}{6x}$$

Cancel out 2\times 3x in both numerator and denominator.

$$3x$$

Differentiate w.r.t. x

$$3$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{18x}{6}x^{1-1})$$

Do the arithmetic.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3xx^{0})$$

For any number a except 0, a^{0}=1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x)$$

The derivative of a constant term is 0.

$$0$$