Solve (10+2)(2*10-3)-2*10^2+6/10-5

$$\frac{ (10+2)(2 \times 10-3)-2 \times { 10 }^{ 2 } +6 }{ 10-5 }$$

Evaluate

$$2$$

Solution Steps

Add 10 and 2 to get 12.

$$\frac{12\left(2\times 10-3\right)-2\times 10^{2}+6}{10-5}$$

Multiply 2 and 10 to get 20.

$$\frac{12\left(20-3\right)-2\times 10^{2}+6}{10-5}$$

Subtract 3 from 20 to get 17.

$$\frac{12\times 17-2\times 10^{2}+6}{10-5}$$

Multiply 12 and 17 to get 204.

$$\frac{204-2\times 10^{2}+6}{10-5}$$

Calculate 10 to the power of 2 and get 100.

$$\frac{204-2\times 100+6}{10-5}$$

Multiply 2 and 100 to get 200.

$$\frac{204-200+6}{10-5}$$

Subtract 200 from 204 to get 4.

$$\frac{4+6}{10-5}$$

Add 4 and 6 to get 10.

$$\frac{10}{10-5}$$

Subtract 5 from 10 to get 5.

$$\frac{10}{5}$$

Divide 10 by 5 to get 2.

$$2$$

Factor

$$2$$