Solve (1div(2.9+1))-(1div4)/2.9-3

$$\frac{ (1 \div (2.9+1))-(1 \div 4) }{ 2.9-3 }$$

Evaluate

$$-\frac{5}{78}\approx -0.064102564$$

Solution Steps

Add 2.9 and 1 to get 3.9.

$$\frac{\frac{1}{3.9}-\frac{1}{4}}{2.9-3}$$

Expand \frac{1}{3.9} by multiplying both numerator and the denominator by 10.

$$\frac{\frac{10}{39}-\frac{1}{4}}{2.9-3}$$

Least common multiple of 39 and 4 is 156. Convert \frac{10}{39} and \frac{1}{4} to fractions with denominator 156.

$$\frac{\frac{40}{156}-\frac{39}{156}}{2.9-3}$$

Since \frac{40}{156} and \frac{39}{156} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{40-39}{156}}{2.9-3}$$

Subtract 39 from 40 to get 1.

$$\frac{\frac{1}{156}}{2.9-3}$$

Subtract 3 from 2.9 to get -0.1.

$$\frac{\frac{1}{156}}{-0.1}$$

Express \frac{\frac{1}{156}}{-0.1} as a single fraction.

$$\frac{1}{156\left(-0.1\right)}$$

Multiply 156 and -0.1 to get -15.6.

$$\frac{1}{-15.6}$$

Expand \frac{1}{-15.6} by multiplying both numerator and the denominator by 10.

$$\frac{10}{-156}$$

Reduce the fraction \frac{10}{-156} to lowest terms by extracting and canceling out 2.

$$-\frac{5}{78}$$

Factor

$$-\frac{5}{78} = -0.0641025641025641$$