Solve (2^2)*7^3/8^3*7

$$\frac{ ( { 2 }^{ 2 } ) \times { 7 }^{ 3 } }{ { 8 }^{ 3 } \times 7 }$$

Evaluate

$$\frac{49}{128}=0.3828125$$

Solution Steps

Cancel out 7 in both numerator and denominator.

$$\frac{2^{2}\times 7^{2}}{8^{3}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{4\times 7^{2}}{8^{3}}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{4\times 49}{8^{3}}$$

Multiply 4 and 49 to get 196.

$$\frac{196}{8^{3}}$$

Calculate 8 to the power of 3 and get 512.

$$\frac{196}{512}$$

Reduce the fraction \frac{196}{512} to lowest terms by extracting and canceling out 4.

$$\frac{49}{128}$$

Factor

$$\frac{7 ^ {2}}{2 ^ {7}} = 0.3828125$$