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\frac{\left(x^{3}+125\right)\left(x^{2}+x-56\right)}{\left(x^{2}-49\right)\left(x^{3}-5x^{2}+25x\right)}
Divide \frac{x^{3}+125}{x^{2}-49} by \frac{x^{3}-5x^{2}+25x}{x^{2}+x-56} by multiplying \frac{x^{3}+125}{x^{2}-49} by the reciprocal of \frac{x^{3}-5x^{2}+25x}{x^{2}+x-56}.
\frac{\left(x-7\right)\left(x+5\right)\left(x+8\right)\left(x^{2}-5x+25\right)}{x\left(x-7\right)\left(x+7\right)\left(x^{2}-5x+25\right)}
Factor the expressions that are not already factored.
\frac{\left(x+5\right)\left(x+8\right)}{x\left(x+7\right)}
Cancel out \left(x-7\right)\left(x^{2}-5x+25\right) in both numerator and denominator.
\frac{x^{2}+13x+40}{x^{2}+7x}
Expand the expression.
\frac{\left(x^{3}+125\right)\left(x^{2}+x-56\right)}{\left(x^{2}-49\right)\left(x^{3}-5x^{2}+25x\right)}
Divide \frac{x^{3}+125}{x^{2}-49} by \frac{x^{3}-5x^{2}+25x}{x^{2}+x-56} by multiplying \frac{x^{3}+125}{x^{2}-49} by the reciprocal of \frac{x^{3}-5x^{2}+25x}{x^{2}+x-56}.
\frac{\left(x-7\right)\left(x+5\right)\left(x+8\right)\left(x^{2}-5x+25\right)}{x\left(x-7\right)\left(x+7\right)\left(x^{2}-5x+25\right)}
Factor the expressions that are not already factored.
\frac{\left(x+5\right)\left(x+8\right)}{x\left(x+7\right)}
Cancel out \left(x-7\right)\left(x^{2}-5x+25\right) in both numerator and denominator.
\frac{x^{2}+13x+40}{x^{2}+7x}
Expand the expression.