Solve x^3/3-x^2-3x+4

$$\frac{ { x }^{ 3 } }{ 3 } - { x }^{ 2 } -3x+4$$

Evaluate

$$\frac{x^{3}}{3}-x^{2}-3x+4$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply -x^{2}-3x+4 times \frac{3}{3}.

$$\frac{x^{3}}{3}+\frac{3\left(-x^{2}-3x+4\right)}{3}$$

Since \frac{x^{3}}{3} and \frac{3\left(-x^{2}-3x+4\right)}{3} have the same denominator, add them by adding their numerators.

$$\frac{x^{3}+3\left(-x^{2}-3x+4\right)}{3}$$

Do the multiplications in x^{3}+3\left(-x^{2}-3x+4\right).

$$\frac{x^{3}-3x^{2}-9x+12}{3}$$

Factor

$$\frac{x^{3}-3x^{2}-9x+12}{3}$$

Solution Steps

Factor out \frac{1}{3}. Polynomial x^{3}-3x^{2}-9x+12 is not factored since it does not have any rational roots.

$$\frac{x^{3}-3x^{2}-9x+12}{3}$$