Solve x^2-cos(pi)x/x^2-2cos(pi)x+1

$$\frac{ { x }^{ 2 } - \cos ( \pi ) x }{ { x }^{ 2 } -2 \cos ( \pi ) x+1 }$$

Evaluate

$$\frac{x}{x+1}$$

Short Solution Steps

Get the value of \cos(\pi ) from trigonometric values table.

$$\frac{x^{2}-\left(-x\right)}{x^{2}-2\cos(\pi )x+1}$$

The opposite of -x is x.

$$\frac{x^{2}+x}{x^{2}-2\cos(\pi )x+1}$$

Get the value of \cos(\pi ) from trigonometric values table.

$$\frac{x^{2}+x}{x^{2}-2\left(-1\right)x+1}$$

Multiply 2 and -1 to get -2.

$$\frac{x^{2}+x}{x^{2}-\left(-2x\right)+1}$$

The opposite of -2x is 2x.

$$\frac{x^{2}+x}{x^{2}+2x+1}$$

Factor the expressions that are not already factored.

$$\frac{x\left(x+1\right)}{\left(x+1\right)^{2}}$$

Cancel out x+1 in both numerator and denominator.

$$\frac{x}{x+1}$$

Factor

$$\frac{x}{x+1}$$