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\frac{x^{2}+3-\left(x^{2}-1\right)}{x-1}
Consider \left(x+1\right)\left(x-1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
\frac{x^{2}+3-x^{2}+1}{x-1}
To find the opposite of x^{2}-1, find the opposite of each term.
\frac{3+1}{x-1}
Combine x^{2} and -x^{2} to get 0.
\frac{4}{x-1}
Add 3 and 1 to get 4.
\frac{x^{2}+3-\left(x^{2}-1\right)}{x-1}
Consider \left(x+1\right)\left(x-1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
\frac{x^{2}+3-x^{2}+1}{x-1}
To find the opposite of x^{2}-1, find the opposite of each term.
\frac{3+1}{x-1}
Combine x^{2} and -x^{2} to get 0.
\frac{4}{x-1}
Add 3 and 1 to get 4.