Solve 8^-1*4^-1/2^-3*2^-2

$$\frac{ { 8 }^{ -1 } \times { 4 }^{ -1 } }{ { 2 }^{ -3 } \times { 2 }^{ -2 } }$$

Evaluate

$$1$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -3 and -2 to get -5.

$$\frac{8^{-1}\times 4^{-1}}{2^{-5}}$$

Calculate 8 to the power of -1 and get \frac{1}{8}.

$$\frac{\frac{1}{8}\times 4^{-1}}{2^{-5}}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\frac{\frac{1}{8}\times \frac{1}{4}}{2^{-5}}$$

Multiply \frac{1}{8} and \frac{1}{4} to get \frac{1}{32}.

$$\frac{\frac{1}{32}}{2^{-5}}$$

Calculate 2 to the power of -5 and get \frac{1}{32}.

$$\frac{\frac{1}{32}}{\frac{1}{32}}$$

Divide \frac{1}{32} by \frac{1}{32} to get 1.

$$1$$

Factor

$$1$$