Solve 7^2-4(7)-5/7^2-6(7)-16

$$\frac{ { 7 }^{ 2 } -4(7)-5 }{ { 7 }^{ 2 } -6(7)-16 }$$

Evaluate

$$-\frac{16}{9}\approx -1.777777778$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$\frac{49-4\times 7-5}{7^{2}-6\times 7-16}$$

Multiply 4 and 7 to get 28.

$$\frac{49-28-5}{7^{2}-6\times 7-16}$$

Subtract 28 from 49 to get 21.

$$\frac{21-5}{7^{2}-6\times 7-16}$$

Subtract 5 from 21 to get 16.

$$\frac{16}{7^{2}-6\times 7-16}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{16}{49-6\times 7-16}$$

Multiply 6 and 7 to get 42.

$$\frac{16}{49-42-16}$$

Subtract 42 from 49 to get 7.

$$\frac{16}{7-16}$$

Subtract 16 from 7 to get -9.

$$\frac{16}{-9}$$

Fraction \frac{16}{-9} can be rewritten as -\frac{16}{9} by extracting the negative sign.

$$-\frac{16}{9}$$

Factor

$$-\frac{16}{9} = -1\frac{7}{9} = -1.7777777777777777$$