Solve 4^4/3-4^4/4

$$\frac{ { 4 }^{ 4 } }{ 3 } - \frac{ { 4 }^{ 4 } }{ 4 }$$

Evaluate

$$\frac{64}{3}\approx 21.333333333$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 4 to get 3.

$$\frac{4^{4}}{3}-4^{3}$$

Calculate 4 to the power of 4 and get 256.

$$\frac{256}{3}-4^{3}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{256}{3}-64$$

Convert 64 to fraction \frac{192}{3}.

$$\frac{256}{3}-\frac{192}{3}$$

Since \frac{256}{3} and \frac{192}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{256-192}{3}$$

Subtract 192 from 256 to get 64.

$$\frac{64}{3}$$

Factor

$$\frac{2 ^ {6}}{3} = 21\frac{1}{3} = 21.333333333333332$$