Solve 4^2+2+4^2/2^2left(.2right)^2

$$\frac{ { 4 }^{ 2 } +2+ { 4 }^{ 2 } }{ { 2 }^{ 2 } { \left(.2 \right) }^{ 2 } }$$

Evaluate

$$212.5$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\frac{16+2+4^{2}}{2^{2}\times 0.2^{2}}$$

Add 16 and 2 to get 18.

$$\frac{18+4^{2}}{2^{2}\times 0.2^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{18+16}{2^{2}\times 0.2^{2}}$$

Add 18 and 16 to get 34.

$$\frac{34}{2^{2}\times 0.2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{34}{4\times 0.2^{2}}$$

Calculate 0.2 to the power of 2 and get 0.04.

$$\frac{34}{4\times 0.04}$$

Multiply 4 and 0.04 to get 0.16.

$$\frac{34}{0.16}$$

Expand \frac{34}{0.16} by multiplying both numerator and the denominator by 100.

$$\frac{3400}{16}$$

Reduce the fraction \frac{3400}{16} to lowest terms by extracting and canceling out 8.

$$\frac{425}{2}$$

Factor

$$\frac{17 \cdot 5 ^ {2}}{2} = 212\frac{1}{2} = 212.5$$