Solve 3^4/4-4*3^3/3+2*3^2+3

$$\frac{ { 3 }^{ 4 } }{ 4 } - \frac{ 4 \times { 3 }^{ 3 } }{ 3 } +2 \times { 3 }^{ 2 } +3$$

Evaluate

$$\frac{21}{4}=5.25$$

Solution Steps

Calculate 3 to the power of 4 and get 81.

$$\frac{81}{4}-\frac{4\times 3^{3}}{3}+2\times 3^{2}+3$$

Calculate 3 to the power of 3 and get 27.

$$\frac{81}{4}-\frac{4\times 27}{3}+2\times 3^{2}+3$$

Multiply 4 and 27 to get 108.

$$\frac{81}{4}-\frac{108}{3}+2\times 3^{2}+3$$

Divide 108 by 3 to get 36.

$$\frac{81}{4}-36+2\times 3^{2}+3$$

Convert 36 to fraction \frac{144}{4}.

$$\frac{81}{4}-\frac{144}{4}+2\times 3^{2}+3$$

Since \frac{81}{4} and \frac{144}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{81-144}{4}+2\times 3^{2}+3$$

Subtract 144 from 81 to get -63.

$$-\frac{63}{4}+2\times 3^{2}+3$$

Calculate 3 to the power of 2 and get 9.

$$-\frac{63}{4}+2\times 9+3$$

Multiply 2 and 9 to get 18.

$$-\frac{63}{4}+18+3$$

Convert 18 to fraction \frac{72}{4}.

$$-\frac{63}{4}+\frac{72}{4}+3$$

Since -\frac{63}{4} and \frac{72}{4} have the same denominator, add them by adding their numerators.

$$\frac{-63+72}{4}+3$$

Add -63 and 72 to get 9.

$$\frac{9}{4}+3$$

Convert 3 to fraction \frac{12}{4}.

$$\frac{9}{4}+\frac{12}{4}$$

Since \frac{9}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.

$$\frac{9+12}{4}$$

Add 9 and 12 to get 21.

$$\frac{21}{4}$$

Factor

$$\frac{3 \cdot 7}{2 ^ {2}} = 5\frac{1}{4} = 5.25$$