Solve 2^30+2^29+2^28/2^31+{2^30-{2}^29}=7/10

$$\frac{ { 2 }^{ 30 } + { 2 }^{ 29 } + { 2 }^{ 28 } }{ { 2 }^{ 31 } + { 2 }^{ 30 } - { 2 }^{ 29 } } = \frac{ 7 }{ 10 }$$

Verify

Solution Steps

Calculate 2 to the power of 30 and get 1073741824.

$$\frac{1073741824+2^{29}+2^{28}}{2^{31}+2^{30}-2^{29}}=\frac{7}{10}$$

Calculate 2 to the power of 29 and get 536870912.

$$\frac{1073741824+536870912+2^{28}}{2^{31}+2^{30}-2^{29}}=\frac{7}{10}$$

Add 1073741824 and 536870912 to get 1610612736.

$$\frac{1610612736+2^{28}}{2^{31}+2^{30}-2^{29}}=\frac{7}{10}$$

Calculate 2 to the power of 28 and get 268435456.

$$\frac{1610612736+268435456}{2^{31}+2^{30}-2^{29}}=\frac{7}{10}$$

Add 1610612736 and 268435456 to get 1879048192.

$$\frac{1879048192}{2^{31}+2^{30}-2^{29}}=\frac{7}{10}$$

Calculate 2 to the power of 31 and get 2147483648.

$$\frac{1879048192}{2147483648+2^{30}-2^{29}}=\frac{7}{10}$$

Calculate 2 to the power of 30 and get 1073741824.

$$\frac{1879048192}{2147483648+1073741824-2^{29}}=\frac{7}{10}$$

Add 2147483648 and 1073741824 to get 3221225472.

$$\frac{1879048192}{3221225472-2^{29}}=\frac{7}{10}$$

Calculate 2 to the power of 29 and get 536870912.

$$\frac{1879048192}{3221225472-536870912}=\frac{7}{10}$$

Subtract 536870912 from 3221225472 to get 2684354560.

$$\frac{1879048192}{2684354560}=\frac{7}{10}$$

Reduce the fraction \frac{1879048192}{2684354560} to lowest terms by extracting and canceling out 268435456.

$$\frac{7}{10}=\frac{7}{10}$$

Compare \frac{7}{10} and \frac{7}{10}.

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