Solve 2^2+4*2+4/2^3+42^2

$$\frac{ { 2 }^{ 2 } +4 \cdot 2+4 }{ { 2 }^{ 3 } +4 { 2 }^{ 2 } }$$

Evaluate

$$\frac{2}{3}\approx 0.666666667$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{4+4\times 2+4}{2^{3}+4\times 2^{2}}$$

Multiply 4 and 2 to get 8.

$$\frac{4+8+4}{2^{3}+4\times 2^{2}}$$

Add 4 and 8 to get 12.

$$\frac{12+4}{2^{3}+4\times 2^{2}}$$

Add 12 and 4 to get 16.

$$\frac{16}{2^{3}+4\times 2^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{16}{8+4\times 2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{16}{8+4\times 4}$$

Multiply 4 and 4 to get 16.

$$\frac{16}{8+16}$$

Add 8 and 16 to get 24.

$$\frac{16}{24}$$

Reduce the fraction \frac{16}{24} to lowest terms by extracting and canceling out 8.

$$\frac{2}{3}$$

Factor

$$\frac{2}{3} = 0.6666666666666666$$