Solve 2^2/sqrt{3^2}=left(x+12right)^

$$\frac{ { 2 }^{ 2 } }{ \sqrt{ { 3 }^{ 2 } } } = { \left(x+12 \right) }^{ }$$

Solve for x

$$x = -\frac{32}{3} = -10\frac{2}{3} \approx -10.666666667$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$\frac{4}{\sqrt{3^{2}}}=\left(x+12\right)^{1}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{4}{\sqrt{9}}=\left(x+12\right)^{1}$$

Calculate the square root of 9 and get 3.

$$\frac{4}{3}=\left(x+12\right)^{1}$$

Calculate x+12 to the power of 1 and get x+12.

$$\frac{4}{3}=x+12$$

Swap sides so that all variable terms are on the left hand side.

$$x+12=\frac{4}{3}$$

Subtract 12 from both sides.

$$x=\frac{4}{3}-12$$

Subtract 12 from \frac{4}{3} to get -\frac{32}{3}.

$$x=-\frac{32}{3}$$