Solve 2^-3*2^6/2^-1*4^2

$$\frac{ { 2 }^{ -3 } \times { 2 }^{ 6 } }{ { 2 }^{ -1 } \times { 4 }^{ 2 } }$$

Evaluate

$$1$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -3 and 6 to get 3.

$$\frac{2^{3}}{2^{-1}\times 4^{2}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{2^{4}}{4^{2}}$$

Calculate 2 to the power of 4 and get 16.

$$\frac{16}{4^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{16}{16}$$

Divide 16 by 16 to get 1.

$$1$$

Factor

$$1$$