Solve 2^*(3/2)3/2/sqrt{73/2}

$$\frac{ { 2 }^{ } \times ( \frac{ 3 }{ 2 } ) \frac{ 3 }{ 2 } }{ \frac{ \sqrt{ 73 } }{ 2 } }$$

Evaluate

$$\frac{9\sqrt{73}}{73}\approx 1.053370325$$

Solution Steps

Calculate 2 to the power of 1 and get 2.

$$\frac{2\times \frac{3}{2}\times \frac{3}{2}}{\frac{\sqrt{73}}{2}}$$

Cancel out 2 and 2.

$$\frac{3\times \frac{3}{2}}{\frac{\sqrt{73}}{2}}$$

Express 3\times \frac{3}{2} as a single fraction.

$$\frac{\frac{3\times 3}{2}}{\frac{\sqrt{73}}{2}}$$

Multiply 3 and 3 to get 9.

$$\frac{\frac{9}{2}}{\frac{\sqrt{73}}{2}}$$

Divide \frac{9}{2} by \frac{\sqrt{73}}{2} by multiplying \frac{9}{2} by the reciprocal of \frac{\sqrt{73}}{2}.

$$\frac{9\times 2}{2\sqrt{73}}$$

Cancel out 2 in both numerator and denominator.

$$\frac{9}{\sqrt{73}}$$

Rationalize the denominator of \frac{9}{\sqrt{73}} by multiplying numerator and denominator by \sqrt{73}.

$$\frac{9\sqrt{73}}{\left(\sqrt{73}\right)^{2}}$$

The square of \sqrt{73} is 73.

$$\frac{9\sqrt{73}}{73}$$