Solve 17^-1+4^-1/left(17*4right)^-1

$$\frac{ { 17 }^{ -1 } + { 4 }^{ -1 } }{ { \left(17 \times 4 \right) }^{ -1 } }$$

Evaluate

$$21$$

Solution Steps

Calculate 17 to the power of -1 and get \frac{1}{17}.

$$\frac{\frac{1}{17}+4^{-1}}{\left(17\times 4\right)^{-1}}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\frac{\frac{1}{17}+\frac{1}{4}}{\left(17\times 4\right)^{-1}}$$

Add \frac{1}{17} and \frac{1}{4} to get \frac{21}{68}.

$$\frac{\frac{21}{68}}{\left(17\times 4\right)^{-1}}$$

Multiply 17 and 4 to get 68.

$$\frac{\frac{21}{68}}{68^{-1}}$$

Calculate 68 to the power of -1 and get \frac{1}{68}.

$$\frac{\frac{21}{68}}{\frac{1}{68}}$$

Divide \frac{21}{68} by \frac{1}{68} by multiplying \frac{21}{68} by the reciprocal of \frac{1}{68}.

$$\frac{21}{68}\times 68$$

Multiply \frac{21}{68} and 68 to get 21.

$$21$$

Factor

$$3\times 7$$