Solve 10^2-3^32-4^2*2/7+53^2

$$\frac{ { 10 }^{ 2 } - { 3 }^{ 3 } 2- { 4 }^{ 2 } \times 2 }{ 7 } +5 { 3 }^{ 2 }$$

Evaluate

$$47$$

Solution Steps

Calculate 10 to the power of 2 and get 100.

$$\frac{100-3^{3}\times 2-4^{2}\times 2}{7}+5\times 3^{2}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{100-27\times 2-4^{2}\times 2}{7}+5\times 3^{2}$$

Multiply 27 and 2 to get 54.

$$\frac{100-54-4^{2}\times 2}{7}+5\times 3^{2}$$

Subtract 54 from 100 to get 46.

$$\frac{46-4^{2}\times 2}{7}+5\times 3^{2}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{46-16\times 2}{7}+5\times 3^{2}$$

Multiply 16 and 2 to get 32.

$$\frac{46-32}{7}+5\times 3^{2}$$

Subtract 32 from 46 to get 14.

$$\frac{14}{7}+5\times 3^{2}$$

Divide 14 by 7 to get 2.

$$2+5\times 3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$2+5\times 9$$

Multiply 5 and 9 to get 45.

$$2+45$$

Add 2 and 45 to get 47.

$$47$$

Factor

$$47$$