Solve 0.9^2*0.5(1-0.5)/0.05^2

$$\frac{ { 0.9 }^{ 2 } \times 0.5(1-0.5) }{ { 0.05 }^{ 2 } }$$

Evaluate

$$81$$

Solution Steps

Calculate 0.9 to the power of 2 and get 0.81.

$$\frac{0.81\times 0.5\left(1-0.5\right)}{0.05^{2}}$$

Multiply 0.81 and 0.5 to get 0.405.

$$\frac{0.405\left(1-0.5\right)}{0.05^{2}}$$

Subtract 0.5 from 1 to get 0.5.

$$\frac{0.405\times 0.5}{0.05^{2}}$$

Multiply 0.405 and 0.5 to get 0.2025.

$$\frac{0.2025}{0.05^{2}}$$

Calculate 0.05 to the power of 2 and get 0.0025.

$$\frac{0.2025}{0.0025}$$

Expand \frac{0.2025}{0.0025} by multiplying both numerator and the denominator by 10000.

$$\frac{2025}{25}$$

Divide 2025 by 25 to get 81.

$$81$$

Factor

$$3^{4}$$