Solve left(8-8right)^2+left(9-8right)^2+left(7-8right)^2/3

$$\frac{ { \left(8-8 \right) }^{ 2 } + { \left(9-8 \right) }^{ 2 } + { \left(7-8 \right) }^{ 2 } }{ 3 }$$

Evaluate

$$\frac{2}{3}\approx 0.666666667$$

Solution Steps

Subtract 8 from 8 to get 0.

$$\frac{0^{2}+\left(9-8\right)^{2}+\left(7-8\right)^{2}}{3}$$

Calculate 0 to the power of 2 and get 0.

$$\frac{0+\left(9-8\right)^{2}+\left(7-8\right)^{2}}{3}$$

Subtract 8 from 9 to get 1.

$$\frac{0+1^{2}+\left(7-8\right)^{2}}{3}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{0+1+\left(7-8\right)^{2}}{3}$$

Add 0 and 1 to get 1.

$$\frac{1+\left(7-8\right)^{2}}{3}$$

Subtract 8 from 7 to get -1.

$$\frac{1+\left(-1\right)^{2}}{3}$$

Calculate -1 to the power of 2 and get 1.

$$\frac{1+1}{3}$$

Add 1 and 1 to get 2.

$$\frac{2}{3}$$

Factor

$$\frac{2}{3} = 0.6666666666666666$$