Solve left(7-2right)^2*2+4/sqrt{64+3*4}div27/10

$$\frac{ { \left(7-2 \right) }^{ 2 } \times 2+4 }{ \sqrt{ 64 } +3 \times 4 } \div \frac{ 27 }{ 10 }$$

Evaluate

$$1$$

Solution Steps

Divide \frac{\left(7-2\right)^{2}\times 2+4}{\sqrt{64}+3\times 4} by \frac{27}{10} by multiplying \frac{\left(7-2\right)^{2}\times 2+4}{\sqrt{64}+3\times 4} by the reciprocal of \frac{27}{10}.

$$\frac{\left(\left(7-2\right)^{2}\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Subtract 2 from 7 to get 5.

$$\frac{\left(5^{2}\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{\left(25\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Multiply 25 and 2 to get 50.

$$\frac{\left(50+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Add 50 and 4 to get 54.

$$\frac{54\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Multiply 54 and 10 to get 540.

$$\frac{540}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Calculate the square root of 64 and get 8.

$$\frac{540}{\left(8+3\times 4\right)\times 27}$$

Multiply 3 and 4 to get 12.

$$\frac{540}{\left(8+12\right)\times 27}$$

Add 8 and 12 to get 20.

$$\frac{540}{20\times 27}$$

Multiply 20 and 27 to get 540.

$$\frac{540}{540}$$

Divide 540 by 540 to get 1.

$$1$$

Factor

$$1$$