Solve left(7*33-42*11right)^2/49*44*18*75

$$\frac{ { \left(7 \times 33-42 \times 11 \right) }^{ 2 } }{ 49 \times 44 \times 18 \times 75 }$$

Evaluate

$$\frac{11}{600}\approx 0.018333333$$

Solution Steps

Multiply 7 and 33 to get 231.

$$\frac{\left(231-42\times 11\right)^{2}}{49\times 44\times 18\times 75}$$

Multiply 42 and 11 to get 462.

$$\frac{\left(231-462\right)^{2}}{49\times 44\times 18\times 75}$$

Subtract 462 from 231 to get -231.

$$\frac{\left(-231\right)^{2}}{49\times 44\times 18\times 75}$$

Calculate -231 to the power of 2 and get 53361.

$$\frac{53361}{49\times 44\times 18\times 75}$$

Multiply 49 and 44 to get 2156.

$$\frac{53361}{2156\times 18\times 75}$$

Multiply 2156 and 18 to get 38808.

$$\frac{53361}{38808\times 75}$$

Multiply 38808 and 75 to get 2910600.

$$\frac{53361}{2910600}$$

Reduce the fraction \frac{53361}{2910600} to lowest terms by extracting and canceling out 4851.

$$\frac{11}{600}$$

Factor

$$\frac{11}{2 ^ {3} \cdot 3 \cdot 5 ^ {2}} = 0.018333333333333333$$