Solve left(5+3right)^2-left(5-3right)^2/left(5+3right)^2+left(5-3right)^2+2/17

$$\frac{ { \left(5+3 \right) }^{ 2 } - { \left(5-3 \right) }^{ 2 } }{ { \left(5+3 \right) }^{ 2 } + { \left(5-3 \right) }^{ 2 } } + \frac{ 2 }{ 17 }$$

Evaluate

$$1$$

Solution Steps

Add 5 and 3 to get 8.

$$\frac{8^{2}-\left(5-3\right)^{2}}{\left(5+3\right)^{2}+\left(5-3\right)^{2}}+\frac{2}{17}$$

Calculate 8 to the power of 2 and get 64.

$$\frac{64-\left(5-3\right)^{2}}{\left(5+3\right)^{2}+\left(5-3\right)^{2}}+\frac{2}{17}$$

Subtract 3 from 5 to get 2.

$$\frac{64-2^{2}}{\left(5+3\right)^{2}+\left(5-3\right)^{2}}+\frac{2}{17}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{64-4}{\left(5+3\right)^{2}+\left(5-3\right)^{2}}+\frac{2}{17}$$

Subtract 4 from 64 to get 60.

$$\frac{60}{\left(5+3\right)^{2}+\left(5-3\right)^{2}}+\frac{2}{17}$$

Add 5 and 3 to get 8.

$$\frac{60}{8^{2}+\left(5-3\right)^{2}}+\frac{2}{17}$$

Calculate 8 to the power of 2 and get 64.

$$\frac{60}{64+\left(5-3\right)^{2}}+\frac{2}{17}$$

Subtract 3 from 5 to get 2.

$$\frac{60}{64+2^{2}}+\frac{2}{17}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{60}{64+4}+\frac{2}{17}$$

Add 64 and 4 to get 68.

$$\frac{60}{68}+\frac{2}{17}$$

Reduce the fraction \frac{60}{68} to lowest terms by extracting and canceling out 4.

$$\frac{15}{17}+\frac{2}{17}$$

Add \frac{15}{17} and \frac{2}{17} to get 1.

$$1$$

Factor

$$1$$