Solve frac{{left(4sqrt{10}right)}^2+69.8*48}{5}

$$\frac{ { \left(4 \sqrt{ 10 } \right) }^{ 2 } +69.8 \times 48 }{ 5 }$$

Evaluate

$$702.08$$

Solution Steps

Expand \left(4\sqrt{10}\right)^{2}.

$$\frac{4^{2}\left(\sqrt{10}\right)^{2}+69.8\times 48}{5}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{16\left(\sqrt{10}\right)^{2}+69.8\times 48}{5}$$

The square of \sqrt{10} is 10.

$$\frac{16\times 10+69.8\times 48}{5}$$

Multiply 16 and 10 to get 160.

$$\frac{160+69.8\times 48}{5}$$

Multiply 69.8 and 48 to get 3350.4.

$$\frac{160+3350.4}{5}$$

Add 160 and 3350.4 to get 3510.4.

$$\frac{3510.4}{5}$$

Expand \frac{3510.4}{5} by multiplying both numerator and the denominator by 10.

$$\frac{35104}{50}$$

Reduce the fraction \frac{35104}{50} to lowest terms by extracting and canceling out 2.

$$\frac{17552}{25}$$

Factor

$$\frac{1097 \cdot 2 ^ {4}}{5 ^ {2}} = 702\frac{2}{25} = 702.08$$