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\frac{1-2\sqrt{3}+\left(\sqrt{3}\right)^{2}}{\left(\sqrt{2}\right)^{2}}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(1-\sqrt{3}\right)^{2}.
\frac{1-2\sqrt{3}+3}{\left(\sqrt{2}\right)^{2}}
The square of \sqrt{3} is 3.
\frac{4-2\sqrt{3}}{\left(\sqrt{2}\right)^{2}}
Add 1 and 3 to get 4.
\frac{4-2\sqrt{3}}{2}
The square of \sqrt{2} is 2.
2-\sqrt{3}
Divide each term of 4-2\sqrt{3} by 2 to get 2-\sqrt{3}.