Solve frac{sqrt{6}+sqrt{2}}{4}+frac{sqrt{3}}{2}=

$$\frac{ \sqrt{ 6 } + \sqrt{ 2 } }{ 4 } + \frac{ \sqrt{ 3 } }{ 2 } =$$

Evaluate

$$\frac{\sqrt{2}+\sqrt{6}+2\sqrt{3}}{4}\approx 1.83195123$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 4 and 2 is 4. Multiply \frac{\sqrt{3}}{2} times \frac{2}{2}.

$$\frac{\sqrt{6}+\sqrt{2}}{4}+\frac{2\sqrt{3}}{4}$$

Since \frac{\sqrt{6}+\sqrt{2}}{4} and \frac{2\sqrt{3}}{4} have the same denominator, add them by adding their numerators.

$$\frac{\sqrt{6}+\sqrt{2}+2\sqrt{3}}{4}$$

Factor

$$\frac{\sqrt{2} + \sqrt{6} + 2 \sqrt{3}}{4} = 1.8319512300735068$$