Solve frac{sqrt{3x}}{2}-12=-10

$$\frac{ \sqrt{ 3x } }{ 2 } -12=-10$$

Solve for x

$$x = \frac{16}{3} = 5\frac{1}{3} \approx 5.333333333$$

Steps for Solving Radical Equations

Add 12 to both sides of the equation.

$$\frac{1}{2}\sqrt{3x}-12-\left(-12\right)=-10-\left(-12\right)$$

Subtracting -12 from itself leaves 0.

$$\frac{1}{2}\sqrt{3x}=-10-\left(-12\right)$$

Subtract -12 from -10.

$$\frac{1}{2}\sqrt{3x}=2$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}\sqrt{3x}}{\frac{1}{2}}=\frac{2}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$\sqrt{3x}=\frac{2}{\frac{1}{2}}$$

Divide 2 by \frac{1}{2} by multiplying 2 by the reciprocal of \frac{1}{2}.

$$\sqrt{3x}=4$$

Square both sides of the equation.

$$3x=16$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{16}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{16}{3}$$