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\frac{\left(\sqrt{17}-\frac{3}{4}\right)\sqrt{15}}{\frac{3}{4}\left(\sqrt{15}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{17}-\frac{3}{4}}{\frac{3}{4}\sqrt{15}} by multiplying numerator and denominator by \sqrt{15}.
\frac{\left(\sqrt{17}-\frac{3}{4}\right)\sqrt{15}}{\frac{3}{4}\times 15}
The square of \sqrt{15} is 15.
\frac{\left(\sqrt{17}-\frac{3}{4}\right)\sqrt{15}}{\frac{3\times 15}{4}}
Express \frac{3}{4}\times 15 as a single fraction.
\frac{\left(\sqrt{17}-\frac{3}{4}\right)\sqrt{15}}{\frac{45}{4}}
Multiply 3 and 15 to get 45.
\frac{\left(\sqrt{17}-\frac{3}{4}\right)\sqrt{15}\times 4}{45}
Divide \left(\sqrt{17}-\frac{3}{4}\right)\sqrt{15} by \frac{45}{4} by multiplying \left(\sqrt{17}-\frac{3}{4}\right)\sqrt{15} by the reciprocal of \frac{45}{4}.
\frac{\left(\sqrt{17}\sqrt{15}-\frac{3}{4}\sqrt{15}\right)\times 4}{45}
Use the distributive property to multiply \sqrt{17}-\frac{3}{4} by \sqrt{15}.
\frac{\left(\sqrt{255}-\frac{3}{4}\sqrt{15}\right)\times 4}{45}
To multiply \sqrt{17} and \sqrt{15}, multiply the numbers under the square root.
\frac{4\sqrt{255}-\frac{3}{4}\sqrt{15}\times 4}{45}
Use the distributive property to multiply \sqrt{255}-\frac{3}{4}\sqrt{15} by 4.
\frac{4\sqrt{255}-3\sqrt{15}}{45}
Cancel out 4 and 4.