Solve frac{sqrt{-1^2+1^2-4*(-3)}}{}

$$\frac{ \sqrt{ - { 1 }^{ 2 } + { 1 }^{ 2 } -4 \times (-3) } }{ }$$

Evaluate

$$2\sqrt{3}\approx 3.464101615$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$\frac{\sqrt{-1+1^{2}-4\left(-3\right)}}{1}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{\sqrt{-1+1-4\left(-3\right)}}{1}$$

Add -1 and 1 to get 0.

$$\frac{\sqrt{0-4\left(-3\right)}}{1}$$

Multiply 4 and -3 to get -12.

$$\frac{\sqrt{0-\left(-12\right)}}{1}$$

The opposite of -12 is 12.

$$\frac{\sqrt{0+12}}{1}$$

Add 0 and 12 to get 12.

$$\frac{\sqrt{12}}{1}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$\frac{2\sqrt{3}}{1}$$

Anything divided by one gives itself.

$$2\sqrt{3}$$