Solve left(2*4+1right)left(left(4+1right)x+(3*4+2right)/2*4+3=4+5

$$\frac{ \left( 2 \cdot 4+1 \right) \left( \left( 4+1 \right) x+(3 \cdot 4+2 \right) }{ 2 \cdot 4+3 } = 4+5$$

Solve for x

$$x=-\frac{3}{5}=-0.6$$

Steps for Solving Linear Equation

Multiply 2 and 4 to get 8.

$$\frac{\left(8+1\right)\left(\left(4+1\right)x+3\times 4+2\right)}{2\times 4+3}=4+5$$

Add 8 and 1 to get 9.

$$\frac{9\left(\left(4+1\right)x+3\times 4+2\right)}{2\times 4+3}=4+5$$

Add 4 and 1 to get 5.

$$\frac{9\left(5x+3\times 4+2\right)}{2\times 4+3}=4+5$$

Multiply 3 and 4 to get 12.

$$\frac{9\left(5x+12+2\right)}{2\times 4+3}=4+5$$

Add 12 and 2 to get 14.

$$\frac{9\left(5x+14\right)}{2\times 4+3}=4+5$$

Multiply 2 and 4 to get 8.

$$\frac{9\left(5x+14\right)}{8+3}=4+5$$

Add 8 and 3 to get 11.

$$\frac{9\left(5x+14\right)}{11}=4+5$$

Add 4 and 5 to get 9.

$$\frac{9\left(5x+14\right)}{11}=9$$

Use the distributive property to multiply 9 by 5x+14.

$$\frac{45x+126}{11}=9$$

Divide each term of 45x+126 by 11 to get \frac{45}{11}x+\frac{126}{11}.

$$\frac{45}{11}x+\frac{126}{11}=9$$

Subtract \frac{126}{11} from both sides.

$$\frac{45}{11}x=9-\frac{126}{11}$$

Convert 9 to fraction \frac{99}{11}.

$$\frac{45}{11}x=\frac{99}{11}-\frac{126}{11}$$

Since \frac{99}{11} and \frac{126}{11} have the same denominator, subtract them by subtracting their numerators.

$$\frac{45}{11}x=\frac{99-126}{11}$$

Subtract 126 from 99 to get -27.

$$\frac{45}{11}x=-\frac{27}{11}$$

Multiply both sides by \frac{11}{45}, the reciprocal of \frac{45}{11}.

$$x=-\frac{27}{11}\times \frac{11}{45}$$

Multiply -\frac{27}{11} times \frac{11}{45} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-27\times 11}{11\times 45}$$

Cancel out 11 in both numerator and denominator.

$$x=\frac{-27}{45}$$

Reduce the fraction \frac{-27}{45} to lowest terms by extracting and canceling out 9.

$$x=-\frac{3}{5}$$