Solve left|-2-4right|/sqrt{1+0^2}

$$\frac{ \left| -2-4 \right| }{ \sqrt{ 1+ { 0 }^{ 2 } } }$$

Evaluate

$$6$$

Solution Steps

Subtract 4 from -2 to get -6.

$$\frac{|-6|}{\sqrt{1+0^{2}}}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -6 is 6.

$$\frac{6}{\sqrt{1+0^{2}}}$$

Calculate 0 to the power of 2 and get 0.

$$\frac{6}{\sqrt{1+0}}$$

Add 1 and 0 to get 1.

$$\frac{6}{\sqrt{1}}$$

Calculate the square root of 1 and get 1.

$$\frac{6}{1}$$

Anything divided by one gives itself.

$$6$$

Factor

$$2\times 3$$