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\frac{\frac{5}{3}+\frac{4\times 7}{3\times 5}}{\frac{\frac{14}{4}}{\frac{6}{5}}}
Multiply \frac{4}{3} times \frac{7}{5} by multiplying numerator times numerator and denominator times denominator.
\frac{\frac{5}{3}+\frac{28}{15}}{\frac{\frac{14}{4}}{\frac{6}{5}}}
Do the multiplications in the fraction \frac{4\times 7}{3\times 5}.
\frac{\frac{25}{15}+\frac{28}{15}}{\frac{\frac{14}{4}}{\frac{6}{5}}}
Least common multiple of 3 and 15 is 15. Convert \frac{5}{3} and \frac{28}{15} to fractions with denominator 15.
\frac{\frac{25+28}{15}}{\frac{\frac{14}{4}}{\frac{6}{5}}}
Since \frac{25}{15} and \frac{28}{15} have the same denominator, add them by adding their numerators.
\frac{\frac{53}{15}}{\frac{\frac{14}{4}}{\frac{6}{5}}}
Add 25 and 28 to get 53.
\frac{\frac{53}{15}}{\frac{14\times 5}{4\times 6}}
Divide \frac{14}{4} by \frac{6}{5} by multiplying \frac{14}{4} by the reciprocal of \frac{6}{5}.
\frac{\frac{53}{15}}{\frac{5\times 7}{2\times 6}}
Cancel out 2 in both numerator and denominator.
\frac{\frac{53}{15}}{\frac{35}{2\times 6}}
Multiply 5 and 7 to get 35.
\frac{\frac{53}{15}}{\frac{35}{12}}
Multiply 2 and 6 to get 12.
\frac{53}{15}\times \frac{12}{35}
Divide \frac{53}{15} by \frac{35}{12} by multiplying \frac{53}{15} by the reciprocal of \frac{35}{12}.
\frac{53\times 12}{15\times 35}
Multiply \frac{53}{15} times \frac{12}{35} by multiplying numerator times numerator and denominator times denominator.
\frac{636}{525}
Do the multiplications in the fraction \frac{53\times 12}{15\times 35}.
\frac{212}{175}
Reduce the fraction \frac{636}{525} to lowest terms by extracting and canceling out 3.