Solve 4/3+1/3+1+3(3)

$$\frac{ \frac{ 4 }{ 3+1 } }{ 3+1 } +3(3)$$

Evaluate

$$\frac{37}{4}=9.25$$

Solution Steps

Add 3 and 1 to get 4.

$$\frac{\frac{4}{4}}{3+1}+3\times 3$$

Divide 4 by 4 to get 1.

$$\frac{1}{3+1}+3\times 3$$

Add 3 and 1 to get 4.

$$\frac{1}{4}+3\times 3$$

Multiply 3 and 3 to get 9.

$$\frac{1}{4}+9$$

Convert 9 to fraction \frac{36}{4}.

$$\frac{1}{4}+\frac{36}{4}$$

Since \frac{1}{4} and \frac{36}{4} have the same denominator, add them by adding their numerators.

$$\frac{1+36}{4}$$

Add 1 and 36 to get 37.

$$\frac{37}{4}$$

Factor

$$\frac{37}{2 ^ {2}} = 9\frac{1}{4} = 9.25$$