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\frac{\left(3a^{2}+a-2\right)\left(4a^{2}-5a-6\right)}{\left(4a^{2}+7a+3\right)\left(3a^{2}-8a+4\right)}
Divide \frac{3a^{2}+a-2}{4a^{2}+7a+3} by \frac{3a^{2}-8a+4}{4a^{2}-5a-6} by multiplying \frac{3a^{2}+a-2}{4a^{2}+7a+3} by the reciprocal of \frac{3a^{2}-8a+4}{4a^{2}-5a-6}.
\frac{\left(a-2\right)\left(3a-2\right)\left(a+1\right)\left(4a+3\right)}{\left(a-2\right)\left(3a-2\right)\left(a+1\right)\left(4a+3\right)}
Factor the expressions that are not already factored.
1
Cancel out \left(a-2\right)\left(3a-2\right)\left(a+1\right)\left(4a+3\right) in both numerator and denominator.