Solve 28/2^3/4^32

$$\frac{ \frac{ 28 }{ { 2 }^{ 3 } } }{ { 4 }^{ 3 } 2 }$$

Evaluate

$$\frac{7}{256}=0.02734375$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{\frac{28}{8}}{4^{3}\times 2}$$

Reduce the fraction \frac{28}{8} to lowest terms by extracting and canceling out 4.

$$\frac{\frac{7}{2}}{4^{3}\times 2}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{\frac{7}{2}}{64\times 2}$$

Multiply 64 and 2 to get 128.

$$\frac{\frac{7}{2}}{128}$$

Express \frac{\frac{7}{2}}{128} as a single fraction.

$$\frac{7}{2\times 128}$$

Multiply 2 and 128 to get 256.

$$\frac{7}{256}$$

Factor

$$\frac{7}{2 ^ {8}} = 0.02734375$$