Solve 2/x+5/x^2/frac{4{x^2}-25/x}

$$\frac{ \frac{ 2 }{ x } + \frac{ 5 }{ { x }^{ 2 } } }{ \frac{ 4 }{ { x }^{ 2 } } - \frac{ 25 }{ x } }$$

Evaluate

$$-\frac{2x+5}{25x-4}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x and x^{2} is x^{2}. Multiply \frac{2}{x} times \frac{x}{x}.

$$\frac{\frac{2x}{x^{2}}+\frac{5}{x^{2}}}{\frac{4}{x^{2}}-\frac{25}{x}}$$

Since \frac{2x}{x^{2}} and \frac{5}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\frac{2x+5}{x^{2}}}{\frac{4}{x^{2}}-\frac{25}{x}}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x^{2} and x is x^{2}. Multiply \frac{25}{x} times \frac{x}{x}.

$$\frac{\frac{2x+5}{x^{2}}}{\frac{4}{x^{2}}-\frac{25x}{x^{2}}}$$

Since \frac{4}{x^{2}} and \frac{25x}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{2x+5}{x^{2}}}{\frac{4-25x}{x^{2}}}$$

Divide \frac{2x+5}{x^{2}} by \frac{4-25x}{x^{2}} by multiplying \frac{2x+5}{x^{2}} by the reciprocal of \frac{4-25x}{x^{2}}.

$$\frac{\left(2x+5\right)x^{2}}{x^{2}\left(4-25x\right)}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{2x+5}{-25x+4}$$

Expand

$$\frac{2x+5}{4-25x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x and x^{2} is x^{2}. Multiply \frac{2}{x} times \frac{x}{x}.

$$\frac{\frac{2x}{x^{2}}+\frac{5}{x^{2}}}{\frac{4}{x^{2}}-\frac{25}{x}}$$

Since \frac{2x}{x^{2}} and \frac{5}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\frac{2x+5}{x^{2}}}{\frac{4}{x^{2}}-\frac{25}{x}}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x^{2} and x is x^{2}. Multiply \frac{25}{x} times \frac{x}{x}.

$$\frac{\frac{2x+5}{x^{2}}}{\frac{4}{x^{2}}-\frac{25x}{x^{2}}}$$

Since \frac{4}{x^{2}} and \frac{25x}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{2x+5}{x^{2}}}{\frac{4-25x}{x^{2}}}$$

Divide \frac{2x+5}{x^{2}} by \frac{4-25x}{x^{2}} by multiplying \frac{2x+5}{x^{2}} by the reciprocal of \frac{4-25x}{x^{2}}.

$$\frac{\left(2x+5\right)x^{2}}{x^{2}\left(4-25x\right)}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{2x+5}{-25x+4}$$