Solve 13/1/frac{10{9}+25/9+4/9}-frac{15}{9}

$$\frac{ \frac{ 13 }{ 1 } }{ \frac{ 10 }{ 9 } + \frac{ 25 }{ 9 } + \frac{ 4 }{ 9 } } - \frac{ 15 }{ 9 }$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Anything divided by one gives itself.

$$\frac{13}{\frac{10}{9}+\frac{25}{9}+\frac{4}{9}}-\frac{15}{9}$$

Since \frac{10}{9} and \frac{25}{9} have the same denominator, add them by adding their numerators.

$$\frac{13}{\frac{10+25}{9}+\frac{4}{9}}-\frac{15}{9}$$

Add 10 and 25 to get 35.

$$\frac{13}{\frac{35}{9}+\frac{4}{9}}-\frac{15}{9}$$

Since \frac{35}{9} and \frac{4}{9} have the same denominator, add them by adding their numerators.

$$\frac{13}{\frac{35+4}{9}}-\frac{15}{9}$$

Add 35 and 4 to get 39.

$$\frac{13}{\frac{39}{9}}-\frac{15}{9}$$

Reduce the fraction \frac{39}{9} to lowest terms by extracting and canceling out 3.

$$\frac{13}{\frac{13}{3}}-\frac{15}{9}$$

Divide 13 by \frac{13}{3} by multiplying 13 by the reciprocal of \frac{13}{3}.

$$13\times \frac{3}{13}-\frac{15}{9}$$

Cancel out 13 and 13.

$$3-\frac{15}{9}$$

Reduce the fraction \frac{15}{9} to lowest terms by extracting and canceling out 3.

$$3-\frac{5}{3}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{9}{3}-\frac{5}{3}$$

Since \frac{9}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-5}{3}$$

Subtract 5 from 9 to get 4.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$