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3\times \frac{1}{3}x\geq 1x
Multiply both sides of the equation by 6, the least common multiple of 2,6. Since 6 is positive, the inequality direction remains the same.
x\geq 1x
Cancel out 3 and 3.
x-x\geq 0
Subtract 1x from both sides.
0\geq 0
Combine x and -x to get 0.
x\in \mathrm{R}
This is true for any x.