Solve 1^-3/49^-3/frac{1^6{49^6}}

$$\frac{ \frac{ { 1 }^{ -3 } }{ { 49 }^{ -3 } } }{ \frac{ { 1 }^{ 6 } }{ { 49 }^{ 6 } } }$$

Evaluate

$$1628413597910449$$

Solution Steps

Divide \frac{1^{-3}}{49^{-3}} by \frac{1^{6}}{49^{6}} by multiplying \frac{1^{-3}}{49^{-3}} by the reciprocal of \frac{1^{6}}{49^{6}}.

$$\frac{1^{-3}\times 49^{6}}{49^{-3}\times 1^{6}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{1^{-3}\times 49^{9}}{1^{6}}$$

To divide powers of the same base, subtract the numerator's exponent from the denominator's exponent.

$$\frac{49^{9}}{1^{9}}$$

Calculate 49 to the power of 9 and get 1628413597910449.

$$\frac{1628413597910449}{1^{9}}$$

Calculate 1 to the power of 9 and get 1.

$$\frac{1628413597910449}{1}$$

Anything divided by one gives itself.

$$1628413597910449$$

Factor

$$7^{18}$$