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\frac{\frac{\left(-\frac{1}{6}\right)^{2}}{\frac{5}{6}}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Subtract \frac{2}{3} from \frac{1}{2} to get -\frac{1}{6}.
\frac{\frac{\frac{1}{36}}{\frac{5}{6}}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Calculate -\frac{1}{6} to the power of 2 and get \frac{1}{36}.
\frac{\frac{1}{36}\times \frac{6}{5}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Divide \frac{1}{36} by \frac{5}{6} by multiplying \frac{1}{36} by the reciprocal of \frac{5}{6}.
\frac{\frac{1}{30}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Multiply \frac{1}{36} and \frac{6}{5} to get \frac{1}{30}.
\frac{\frac{1}{30}-\frac{1}{3}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Rewrite the square root of the division \frac{1}{9} as the division of square roots \frac{\sqrt{1}}{\sqrt{9}}. Take the square root of both numerator and denominator.
\frac{-\frac{3}{10}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Subtract \frac{1}{3} from \frac{1}{30} to get -\frac{3}{10}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Calculate \sqrt[3]{\frac{1}{8}} and get \frac{1}{2}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\left(\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Subtract \frac{1}{2} from 1 to get \frac{1}{2}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\frac{1}{4}\times \frac{9}{8}}
Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\frac{9}{32}}
Multiply \frac{1}{4} and \frac{9}{8} to get \frac{9}{32}.
\frac{-\frac{3}{10}}{\frac{25}{32}}
Add \frac{1}{2} and \frac{9}{32} to get \frac{25}{32}.
-\frac{3}{10}\times \frac{32}{25}
Divide -\frac{3}{10} by \frac{25}{32} by multiplying -\frac{3}{10} by the reciprocal of \frac{25}{32}.
-\frac{48}{125}
Multiply -\frac{3}{10} and \frac{32}{25} to get -\frac{48}{125}.