Solve for n
n=\frac{7z-51}{2}
z\neq 5
Solve for z
z=\frac{2n+51}{7}
n\neq -8
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7\left(z-5\right)=2\left(n+8\right)
Variable n cannot be equal to -8 since division by zero is not defined. Multiply both sides of the equation by 7\left(n+8\right), the least common multiple of n+8,7.
7z-35=2\left(n+8\right)
Use the distributive property to multiply 7 by z-5.
7z-35=2n+16
Use the distributive property to multiply 2 by n+8.
2n+16=7z-35
Swap sides so that all variable terms are on the left hand side.
2n=7z-35-16
Subtract 16 from both sides.
2n=7z-51
Subtract 16 from -35 to get -51.
\frac{2n}{2}=\frac{7z-51}{2}
Divide both sides by 2.
n=\frac{7z-51}{2}
Dividing by 2 undoes the multiplication by 2.
n=\frac{7z-51}{2}\text{, }n\neq -8
Variable n cannot be equal to -8.
7\left(z-5\right)=2\left(n+8\right)
Multiply both sides of the equation by 7\left(n+8\right), the least common multiple of n+8,7.
7z-35=2\left(n+8\right)
Use the distributive property to multiply 7 by z-5.
7z-35=2n+16
Use the distributive property to multiply 2 by n+8.
7z=2n+16+35
Add 35 to both sides.
7z=2n+51
Add 16 and 35 to get 51.
\frac{7z}{7}=\frac{2n+51}{7}
Divide both sides by 7.
z=\frac{2n+51}{7}
Dividing by 7 undoes the multiplication by 7.
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