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\frac{\left(z^{2}-4\right)\left(z^{2}+z-12\right)}{\left(z-3\right)\left(z+2\right)}
Divide \frac{z^{2}-4}{z-3} by \frac{z+2}{z^{2}+z-12} by multiplying \frac{z^{2}-4}{z-3} by the reciprocal of \frac{z+2}{z^{2}+z-12}.
\frac{\left(z-3\right)\left(z-2\right)\left(z+2\right)\left(z+4\right)}{\left(z-3\right)\left(z+2\right)}
Factor the expressions that are not already factored.
\left(z-2\right)\left(z+4\right)
Cancel out \left(z-3\right)\left(z+2\right) in both numerator and denominator.
z^{2}+2z-8
Expand the expression.
\frac{\left(z^{2}-4\right)\left(z^{2}+z-12\right)}{\left(z-3\right)\left(z+2\right)}
Divide \frac{z^{2}-4}{z-3} by \frac{z+2}{z^{2}+z-12} by multiplying \frac{z^{2}-4}{z-3} by the reciprocal of \frac{z+2}{z^{2}+z-12}.
\frac{\left(z-3\right)\left(z-2\right)\left(z+2\right)\left(z+4\right)}{\left(z-3\right)\left(z+2\right)}
Factor the expressions that are not already factored.
\left(z-2\right)\left(z+4\right)
Cancel out \left(z-3\right)\left(z+2\right) in both numerator and denominator.
z^{2}+2z-8
Expand the expression.