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\frac{\left(z^{2}-2z-3\right)\left(4z+3\right)}{\left(8z^{2}+6z\right)\left(z^{2}-1\right)}
Divide \frac{z^{2}-2z-3}{8z^{2}+6z} by \frac{z^{2}-1}{4z+3} by multiplying \frac{z^{2}-2z-3}{8z^{2}+6z} by the reciprocal of \frac{z^{2}-1}{4z+3}.
\frac{\left(z-3\right)\left(z+1\right)\left(4z+3\right)}{2z\left(z-1\right)\left(z+1\right)\left(4z+3\right)}
Factor the expressions that are not already factored.
\frac{z-3}{2z\left(z-1\right)}
Cancel out \left(z+1\right)\left(4z+3\right) in both numerator and denominator.
\frac{z-3}{2z^{2}-2z}
Expand the expression.
\frac{\left(z^{2}-2z-3\right)\left(4z+3\right)}{\left(8z^{2}+6z\right)\left(z^{2}-1\right)}
Divide \frac{z^{2}-2z-3}{8z^{2}+6z} by \frac{z^{2}-1}{4z+3} by multiplying \frac{z^{2}-2z-3}{8z^{2}+6z} by the reciprocal of \frac{z^{2}-1}{4z+3}.
\frac{\left(z-3\right)\left(z+1\right)\left(4z+3\right)}{2z\left(z-1\right)\left(z+1\right)\left(4z+3\right)}
Factor the expressions that are not already factored.
\frac{z-3}{2z\left(z-1\right)}
Cancel out \left(z+1\right)\left(4z+3\right) in both numerator and denominator.
\frac{z-3}{2z^{2}-2z}
Expand the expression.