Solve for x_0
x_{0}=\frac{2y_{0}}{5}
y_{0}\neq 0
Solve for y_0
y_{0}=\frac{5x_{0}}{2}
x_{0}\neq 0
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y_{0}=\frac{1}{2}x_{0}\left(-\left(-3\right)-\left(-2\right)\right)
Variable x_{0} cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x_{0}.
y_{0}=\frac{1}{2}x_{0}\left(3-\left(-2\right)\right)
The opposite of -3 is 3.
y_{0}=\frac{1}{2}x_{0}\left(3+2\right)
The opposite of -2 is 2.
y_{0}=\frac{1}{2}x_{0}\times 5
Add 3 and 2 to get 5.
y_{0}=\frac{5}{2}x_{0}
Multiply \frac{1}{2} and 5 to get \frac{5}{2}.
\frac{5}{2}x_{0}=y_{0}
Swap sides so that all variable terms are on the left hand side.
\frac{\frac{5}{2}x_{0}}{\frac{5}{2}}=\frac{y_{0}}{\frac{5}{2}}
Divide both sides of the equation by \frac{5}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.
x_{0}=\frac{y_{0}}{\frac{5}{2}}
Dividing by \frac{5}{2} undoes the multiplication by \frac{5}{2}.
x_{0}=\frac{2y_{0}}{5}
Divide y_{0} by \frac{5}{2} by multiplying y_{0} by the reciprocal of \frac{5}{2}.
x_{0}=\frac{2y_{0}}{5}\text{, }x_{0}\neq 0
Variable x_{0} cannot be equal to 0.
y_{0}=\frac{1}{2}x_{0}\left(-\left(-3\right)-\left(-2\right)\right)
Multiply both sides of the equation by x_{0}.
y_{0}=\frac{1}{2}x_{0}\left(3-\left(-2\right)\right)
The opposite of -3 is 3.
y_{0}=\frac{1}{2}x_{0}\left(3+2\right)
The opposite of -2 is 2.
y_{0}=\frac{1}{2}x_{0}\times 5
Add 3 and 2 to get 5.
y_{0}=\frac{5}{2}x_{0}
Multiply \frac{1}{2} and 5 to get \frac{5}{2}.
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